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Syllabus: First order equations (linear and nonlinear), higher order linear differential equations, Cauchy's and Euler's equations, methods of solution using variation of parameters, complementary function and particular integral, partial differential equations, variable separable method, initial and boundary value problems.
10 hand-picked visual resources on this topic, 4 of them little-known gems — under each card, look for See it. Every link is checked against the live site before it ships.
First-order linear
Put it in standard form, multiply by the integrating factor, then integrate once. Everything else is bookkeeping.
standard form
See it
Complementary function and particular integral
For constant-coefficient equations the CF comes from the roots of the auxiliary equation. Repeated roots bring in a factor of — that is what a form is telling you.
Cauchy–Euler equation
Recognise it by the power of matching the order of the derivative. Substituting turns it into a constant-coefficient equation.
PDEs by trial solution
For a linear constant-coefficient PDE, substituting an exponential trial solution collapses the whole equation to an algebraic condition on the exponents — no integration needed.
Wave equation and d'Alembert
Any function of or solves it — a shape travelling right or left without changing. Checking an option reduces to reading off its propagation speed.
Below: on the syllabus, but no past question for it in this bank.
Variation of parameters, and the first-order forms
Use variation of parameters when the right-hand side is not one of the shapes the method of undetermined coefficients handles — , , . For first-order equations, check separable first, then exact, then Bernoulli; only then reach for the integrating factor.
a double root
Where marks are lost
Given a CF of the form , read off a repeated root at , so the equation is .
See it
try
indicial equation
the exponential cancels
See it
speed
general solution
for , with the CF solutions
Wronskian; non-zero means the two solutions are independent
then the solution is
each side depends on a different variable, so both equal a constant
Where marks are lost
The equation must be in standard form — leading coefficient 1 — before is read off. Applying the formula to without dividing by 2 halves every particular solution.